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Learning Math and Coding with Robots

Linkbot Image Mindstorm Image Cursor Image
0x2418126y2418126
Grid:
Tics Lines:
Width px
Hash Lines:
Width px
Labels:
Font px
Trace Lines:
Robot 1:
Width px
Robot 2:
Width px
Robot 3:
Width px
Robot 4:
Width px
Axes: x-axis y-axis Show Grid
Grid: 24x24 inches 36x36 inches 72x72 inches
96x96 inches 192x192 inches
Quad: 4 quadrants 1 quadrant Hardware
Units: US Customary Metric
Background: Background Image

Robot 1
Linkbot
Mindstorm
Initial Position:
( in, in)
Initial Angle:
deg
Current Position: (9 in, 3 in)
Current Angle: 0 deg
Wheel Radius:
Track Width:
in

Robot 2
Linkbot
Mindstorm
Initial Position:
( in, in)
Initial Angle:
deg
Current Position: (0 in, 6 in)
Current Angle: 0 deg
Wheel Radius:
Track Width:
in

Robot 3
Linkbot
Mindstorm
Initial Position:
( in, in)
Initial Angle:
deg
Current Position: (0 in, 12 in)
Current Angle: 0 deg
Wheel Radius:
Track Width:
in

Robot 4
Linkbot
Mindstorm
Initial Position:
( in, in)
Initial Angle:
deg
Current Position: (0 in, 18 in)
Current Angle: 0 deg
Wheel Radius:
Track Width:
in
Reasoning with Shapes: How Many Sides Are There?
Problem Statement:
Run the program using the pre-placed blocks. Use the drawing of the polygon to answer the following question: "How many sides does the shape have?"
/* Code generated by RoboBlockly v2.0 */
/* Problem Statement: 
    Run the program using the pre-placed blocks. Use the
    drawing of the polygon to answer the following question:
    “How many sides does the shape have?”*/
#include <linkbot.h>
CLinkbotI robot;
double radius = 1.75;
double trackwidth = 3.69;
int count;

robot.setSpeed(10, radius);
count = 0;
while(count < 8) {
  robot.driveDistance(8, radius);
  robot.turnLeft(45, radius, trackwidth);
  count = count + 1;
}
printf("There are 8 sides: Hence, this shape is called octagon");
Blocks Save Blocks Load Blocks Show Ch Save Ch Workspace
Problem Statement:
Run the program using the pre-placed blocks. Use the drawing of the polygon to answer the following question: "How many sides does the shape have?"
 

		

			

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